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A projectile A is projected from ground....

A projectile A is projected from ground. An observer B running on ground with uniform velocity of magnitude 'v' observes A to move along a straight line. The time of flight of A as measured by B is T. Then the the range R of projectile on ground is

A

`R=vT`

B

`RltvT`

C

`RgtvT`

D

Information insufficient to draw inference

Text Solution

Verified by Experts

The correct Answer is:
a

The horizontal and vertical components of initial velocity of projectile are as shown in fig. Since the observer moving with uniform velocity v sees the projectile moving in straight line
Hence `v=u cos theta`

The time of flight as measured by observer B `T=(2u sin theta)/g`
Hence horizontal range of projectile on ground
`R=(u cos theta)T=vT`
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