A projectile is fired with initial momentum p at an angle `45^(@)` from a point P as shown in figure. Neglecting air resistance, the magnitude of change in momentum between leaving P and arriving at Q is:

Options

A. `p//2`
B. `psqrt(2)`
C. `p`
D. `2p`

Answer

b

Explanation

Initial momentum =p, Final momentum =-p
Angle between momentum vectors `=270^(@)`
|change in momentum|
`=sqrt(p^(2)+(-p)^(2)+2p(-p)cos 270^(@))=sqrt(2)p`