The maximum height attained by a projectile is increased by 5%. Keeping the angle of projection constant, what is the percentage increases in horizontal range?

Options

A. `5%`
B. `10%`
C. `15%`
D. `20%`

Answer

a

Explanation

If h be the maximum height attained by the projectile then
`h=(u^(2)sin^(2) theta)/(2g) or R=(u^(2)sin2 theta)/g`
`R/h=(2 sin thetacos theta)/((sin^(2) theta)//2) = 4 coth theta`
Therefore `(DeltaR)/R=(Deltah)/h`
`:.` Percentage increases in R=percentage increases in `y_(m)=5%`