Home
Class 11
PHYSICS
A projectile can have same range R for t...

A projectile can have same range `R` for two angles of projection. It `t_1 and t_2` are the times of flight in the two cases, then what is the product of two times of flight ?

A

`t_(1)t_(2) propR^(2)`

B

`t_(1)t_(2) prop R`

C

`t_(1)t_(2) prop1/R`

D

`t_(1)t_(2) prop1/(R^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

For same range angle of projection should be `theta and (90^(@)- theta)`
So, time of flights `t_(1)=(2u sin theta)/g` and
`t_(2)=(2u sin(90^(@)-theta))/g=(2u cos theta)/g`
By multioplying `=t_(1)t_(2)=(4u^(2)sin theta cos theta)/(g^(2))`
`t_(1)t_(2)=(2)/(g) ((u^(2) sin 2 theta))/(g)=(2R)/(g)implies t_(1)t_(2) prop R`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN TWO DIMENSION

    A2Z|Exercise Chapter Test|29 Videos
  • MOTION IN TWO DIMENSION

    A2Z|Exercise NEET Questions|16 Videos
  • MOCK TEST

    A2Z|Exercise Motion With Constant Acceleration|15 Videos
  • NEWTONS LAWS OF MOTION

    A2Z|Exercise Chapter Test|30 Videos

Similar Questions

Explore conceptually related problems

A projectile can have the same range R for two angles of projection. If t_(1) and t_(2) be the times of flight in the two cases:-

A projectile can have the same range R for two angles of projection .If t_1 and t_2 be the times of flight in the two cases, then the product of the two times of fight is directly proportional to

A projectile can have the same range 'R' for two angles of projection . If 'T_(1)' and 'T_(2)' to be times of flights in the two cases, then the product of the two times of flights is directly proportional to .

A projectile can have the same range R for two angle of projection . If t-1 and t_2 be the terms of flight in the two cased then the initial velocity of projectile is?

A projectille can have the same range R for two angles of projection. If t_(1) and t_(2) be the time of flight in the two cases, then find the relation between t_(1), t_(2) and R .

For a given velocity, a projectile has the same range R for two angles of projection. If t_(1) and t_(2) are the time of flight in the two cases, then t_(1) = t_(2) is equal to

For a given velocity, a projectile has the same range R for two angles of rpojection if t_(1) and t_(2) are the times of flight in the two cases then

A projectile has the same range R for two angles of projections but same speed. If T_(1) and T_(2) be the times of flight in the two cases, then Here theta is the angle of projection corresponding to T_(1) .

A projectile has the same range R for angles of projections. If T_(1) and T_(2) be the times of fight in the two cases, then ( using theta as the angle of projection corresponding to T_(1) )