A motor car travelling at `30 m//s` on a circular road of radius `500m`. It is increasing its speed at the rate of `2 ms^(-2)`. What its accleration at that instant ?

Options

A. `2.5ms^(-2)`
B. `2.7ms^(-2)`
C. `2ms^(-2)`
D. `4.5ms^(-2)`

Answer

b

Explanation

Resultant acceleration,
`a=[((v^(2))/r)^(2)+(2)^(2)]^(1//2)=[((30xx30)/500)^(2)+4]^(1//2)`
`=[81/25+4]^(1//2)=2.7ms^(-2)`