A bomber moving horizontally with `500m//s` drops a bomb which strikes ground in 10s. The angle of strike with horizontal is

Options

A. `tan^(-1)(1/5)`
B. `tan(1/5)`
C. `tan^(-1)(1)`
D. `tan^(-1)(5)`

Answer

a

Explanation

Horizontal component of velocity,
`u_(x)=500m//s` and vertical component of velocity while striking the ground.
`v_(y)=0+10xx10=100m//s`

Angle with which is strikes the ground,
`tan theta^(-1)((v_(y))/(v_(x)))=tan^(-1)(100/500)=tan^(-1)(1/5)`