A body of mass 1kg lies on smooth inclined plane. The block of mass `m` is given force `F=10` `N` horizontally as shown. The magnitude of net normal reaction on the block is:

Options

A. `10sqrt(2)N`
B. `10/sqrt(2)N`
C. 10N
D. none of these

Answer

A

Explanation

F.B.D. of block
`N^(2)=F^(2)+(mg)^(2)`
{as there is no acceleration in the direction of `N`}
`N=10sqrt(2)N` .