A body of mass `2.0kg` is placed on a smooth horizontal surface. Two force `F_(1)=20N` and `F_(2)=N` are acting on the body in directions making angles of `30^(@)` and `60^(@)` to the surface. The reaction of the surface om the body will be

Options

A. 20N
B. 25N
C. 5N
D. zero

Answer

D

Explanation

Let us find vertical force:
`F_(1)sin30^(@)+F_(2)sin60^(@)`
`=20xx(1)/(2)+10sqrt(3)((sqrt(3))/(2))=25N`
This is greater than mg. So contact of body with surface will be lost and reaction will be zero.