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In previous question, if we pull the blo...

In previous question, if we pull the block by the force `F` making an angle theta and the block remains stationary, the value of friction force is.

A

`mumg`

B

`Fcostheta`

C

`(mumg)/(sintheta+mucostheta)`

D

`(mumg)/sqrt(1+mu^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

`f_(s)gtFcostheta` (Since block is stationary)
`f=Fcostheta` .
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