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A force of 100N is applied on a block of...

A force of 100N is applied on a block of mass 3kg as shown in the figure. The coefficient of friction between the surface and the block is `mu=(1)/(sqrt(3)` . The friction force acting on the bock is.

A

15N downward

B

25N upward

C

20N downword

D

30N upward

Text Solution

Verified by Experts

The correct Answer is:
C
`N'=100cos30^(@)=100` . `sqrt(3)/(2)=50sqrt(3)N`
Net driving force `=(100xx(1)/(2)-30)`
`=20N` (upward)
`f_(limiting)(1)/(sqrt(3))(50sqrt(3))=50N`
:. friction `=20N` (upward)
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