A box mass m kg is placed on the rear si...

A box mass `m` kg is placed on the rear side of an open truck acceleration at `4ms^(-2)` . The coefficient of friction between the box ant the surface below it is `0.4` . The net acceleration of the box with respect to the truck is zero. The value of `m` is.

4kg

8kg

`9.78kg`

It could be any value

Text Solution

Verified by Experts

The correct Answer is:

Pseudo force on the block
`=mxx4N` (backward)
Force of friction `=0.4xxmxx10N` (forward)
Equating, `mxx4=0.4xxmxx10`
or `4m=4m`
Clearly the equation holds good for all values of `m` .

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