A body of mass 8kg lies on a rough horizontal table. It is observed that a certain horizontal force gives the body an acceleration of the body is `16ms^(-2)` . The coefficient of friction is.

Options

A. `0.2`
B. `0.3`
C. `0.4`
D. `0.8`

Answer

D

Explanation

`F-f=8xx4=32 `(i)
`2F-f=128` (ii)
`"Multiplying"` (i) by (ii), we get
`2F-2f=64` (iii)
Also, (ii)-(iii) gives `f=128-64=64N`
`mumg= muxx8xx10=64` or `mu=(64)/(80)=(80)/(100)=0.8` .