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A block of mass m=2kg is placed in equil...

A block of mass `m=2kg` is placed in equilibrium on a moving plank accelerating with `a=4m//s^(2)` . If coefficient of friction between plank and block `mu=0.2` . The friction force acting on theblock is:

A

8N

B

6N

C

zero

D

4N

Text Solution

Verified by Experts

The correct Answer is:
D
Driving force w.r.t. platform=ma
`=2xx4xx8N`
And resisting force `=f_(lim)=muN`
`=0.2xx2xx10=4N` Here resisting force is sufficient to keep the block at rest w.r.t. plank hence the block will slide on plank and friction force will be `4N` .
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