A block of mass `m` is placed on a rough inclined plane. When the inclination of the plane is `theta` , the block just beging to slide down the plane under its own weight. The minimum force applied parallel to the plane, to move the block up the plane, is.

Options

A. `mgsintheta`
B. `2mgsintheta`
C. `mgcostheta`
D. `mg tantheta`

Answer

B

Explanation

As object just being to slide
`f=mgsintheta`
If we start sliding the block up, the friction force will be downward direction, hence minimum force applied in upward direction.
Component of weight along inclined plane+force of friction
`=2mgsintheta` .