In the arrangement shown in the figure `[sin37^(@)=3//5]` .

Options

A. direction of force of friction is up the plane
B. the mangnitude of force of friction is zero
C. the tension in the string is `20N`
D. magnitude of force of friction is `56N`

Answer

A

Explanation

`f_(lim)=muN=0.7xx80=56N`
Net driving force `=60-40=20N` (down the plane) As resisting force is greater than net driving force, the friction will be static of nature and friction force is `20N` (up the plane)