A small mass slide down an inclined plane of inclination theta with the horizontal. The coefficent of friction is `mu=mu_(0)` `x` where `x` is the distance through which the mass slide down and `mu_(0),a` contant. Then the speed is maxmum after the mass covers a distance of.

Options

A. `(costheta)/(mu_(0))`
B. `(sintheta)/(mu_(0))`
C. `(tantheta)/(mu_(0))`
D. `(2tantheta)/(mu_(0))`

Answer

C

Explanation

Acceleration of mass at distance `x` ,
`a=g(sintheta-mu_0xcostheta)`
Speed is maximum, when `a=0`
implies `g(sintheta-mu_(0)xcostheta)=0`
:. `x=(tantheta)/(mu_(0)` .