A particle is projected along the line of greatest slope up a rough plane inclined at an angle of `45^(@)` with the horizontal. If the coefficient of friction is `1//2` . Their retardation is:

Options

A. `(g)/(2sqrt(2))`
B. `(g)/(sqrt(2))`
C. `(g)/(sqrt(2))(1-(1)/(2))`
D. `(g)/(sqrt(2))(1+(1)/(2))`

Answer

D

Explanation

The retardation a is given by
`a=gsin45^(@)+mugcos45^(@)`
`=(g)/(sqrt(2))+(1)/(2)gxx(1)/(sqrt(2))=(g)/(sqrt(2))(1+(1)/(2))` .