A lift of mass `1000kg` is moving with an acceleration of `1m//s^(2)` in upward direction. Tension developed in the string, which is connected to the lift, is.

Options

A. `9,800N`
B. `10,000N`
C. `10,800N`
D. `11,000N`

Explanation

To find the tension developed in the string connected to the lift, we can use Newton's second law of motion. Here's a step-by-step solution:

### Step 1: Identify the forces acting on the lift
The forces acting on the lift are:
1. The gravitational force (weight) acting downward, which is given by \( W = mg \).
2. The tension \( T \) in the string acting upward.

### Step 2: Write down the known values
- Mass of the lift, \( m = 1000 \, \text{kg} \)
- Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \)
- Acceleration of the lift, \( a = 1 \, \text{m/s}^2 \) (upward)

### Step 3: Apply Newton's second law
According to Newton's second law, the net force acting on the lift can be expressed as:
\[ F_{\text{net}} = T - W \]
Where \( W = mg \). Thus, we can rewrite the equation as:
\[ F_{\text{net}} = T - mg \]

Since the lift is accelerating upwards, we can express the net force as:
\[ F_{\text{net}} = ma \]

### Step 4: Set up the equation
Combining the equations, we have:
\[ T - mg = ma \]

### Step 5: Solve for tension \( T \)
Rearranging the equation gives:
\[ T = mg + ma \]

### Step 6: Substitute the known values
Now we can substitute the values into the equation:
\[ T = (1000 \, \text{kg})(9.8 \, \text{m/s}^2) + (1000 \, \text{kg})(1 \, \text{m/s}^2) \]
Calculating each term:
\[ T = 9800 \, \text{N} + 1000 \, \text{N} = 10800 \, \text{N} \]

### Step 7: Final answer
Thus, the tension developed in the string is:
\[ \boxed{10800 \, \text{N}} \]