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The mass of a lift is 2000kg . When the ...

The mass of a lift is `2000kg` . When the tension in the supporting cable is `28000N` , then its acceleration is.

A

`30ms^(-2)` downwards

B

`4ms^(-2)` upwards

C

`4ms^(-2)` downwards

D

`14ms^(-2)` upwards

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The correct Answer is:
To solve the problem of finding the acceleration of the lift, we can follow these steps: ### Step 1: Identify the forces acting on the lift The two main forces acting on the lift are: 1. The tension (T) in the supporting cable, which acts upwards. 2. The weight (W) of the lift, which acts downwards. The weight of the lift can be calculated using the formula: \[ W = mg \] where: - \( m = 2000 \, \text{kg} \) (mass of the lift) - \( g = 10 \, \text{m/s}^2 \) (acceleration due to gravity) ### Step 2: Calculate the weight of the lift Using the values provided: \[ W = 2000 \, \text{kg} \times 10 \, \text{m/s}^2 = 20000 \, \text{N} \] ### Step 3: Apply Newton's second law of motion According to Newton's second law, the net force acting on the lift is equal to the mass of the lift multiplied by its acceleration (A): \[ F_{\text{net}} = mA \] The net force can also be expressed as the difference between the tension and the weight: \[ F_{\text{net}} = T - W \] ### Step 4: Set up the equation Substituting the expressions for net force, we have: \[ T - W = mA \] ### Step 5: Substitute the known values We know: - \( T = 28000 \, \text{N} \) - \( W = 20000 \, \text{N} \) - \( m = 2000 \, \text{kg} \) Substituting these values into the equation gives: \[ 28000 \, \text{N} - 20000 \, \text{N} = 2000 \, \text{kg} \cdot A \] ### Step 6: Simplify the equation This simplifies to: \[ 8000 \, \text{N} = 2000 \, \text{kg} \cdot A \] ### Step 7: Solve for acceleration (A) Now, divide both sides by 2000 kg: \[ A = \frac{8000 \, \text{N}}{2000 \, \text{kg}} = 4 \, \text{m/s}^2 \] ### Step 8: Determine the direction of acceleration Since the tension is greater than the weight, the acceleration is directed upwards. ### Final Answer: The acceleration of the lift is \( 4 \, \text{m/s}^2 \) upwards. ---

To solve the problem of finding the acceleration of the lift, we can follow these steps: ### Step 1: Identify the forces acting on the lift The two main forces acting on the lift are: 1. The tension (T) in the supporting cable, which acts upwards. 2. The weight (W) of the lift, which acts downwards. The weight of the lift can be calculated using the formula: ...
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Knowledge Check

  • The mass of a lift is 500 kg. What will be the tension in its cable when it is going up with an acceleration of 2.0 m//s^(2) ? (Take, g = 9.8 m//s^(2) )

    A
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    B
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    C
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    D
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    A
    5000 N
    B
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    D
    6200 N
  • When a liftman takes 5 persons in a lift, the totla mass of the lilft and the 5 persons becomes 800 kg. What is the tension in the supporting cable, if the lift ascends with an acceleration of 2m//s^(2) ? (g=10m//s^(2)

    A
    8000N
    B
    8400N
    C
    9000N
    D
    9600N
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