A stone is dropped from a height `h` . It hits the ground with a certain momentum `P` . If the same stone is dropped from a height `100%` more thanthe preyiious height, the momentum when it hits the ground will change by

Options

A. `68%`
B. `41%`
C. `200%`
D. `100%`

Answer

B

Explanation

Velocity `v=sqrt(2gh)`
and momentum `P=mv`
From Eqs. (i) and (ii) we have `Ppropsqrt(h)`
Here `(P_(2))/(P_(1))=sqrt((h_(2))/(h_(1))`
`(P_(2))/(P_(1))=sqrt((2h)/(h))sqrt(2)` :. `p_(2)=1.414p_(1)`
% change `=(P_(2)-P_(1))/(P_(2))xx100=41%`