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A block of mass `m` is placed on a smooth inclined wedge ABC of inclination theta as shown in the figure. The wedge is given an acceleration `a` towards the right. The relation between a and theta for the block to remain stationary on the wedge is.

A

`a=g tantheta`

B

`a=(g)/(cosectheta)`

C

`a=costheta`

D

`a=(g)/(sintheta)`

Text Solution

Verified by Experts

The correct Answer is:
A
If the block is stationary, `macostheta=mgsintheta`
which gives `a=gtantheta` .
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