A particle of mass `200 g` is dropped from a height of `50 m` and another particle of mass `100 g` is simultaneously projected up from the ground along the same lime, with a speed of `100 m//s`. The acceleration of the centre of mass after `1 sec` is.

Options

A. `10 m//s^2`
B. `(10)/(3) m//s^2`
C. 0
D. `9.8 m//s^2`

Answer

D

Explanation

(D) As only force of gravity acts, so acceleration of centre of mass will be `g = 9.8 m//s^2`.