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Two particles of equal mass have velocities `vec v_1 = 2 hat i= m//s^-1` and `vec v_2 = 2hat j m//s^-1`. First particle has an acceleration `vec a_1= (3 hat i+ 3 hat j) ms^-2` while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of.

A

straight line

B

parabola

C

circle

D

ellipse

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To solve the problem, we need to determine the path of the center of mass of two particles given their velocities and accelerations. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the velocities of the particles The velocities of the two particles are given as: - Particle 1: \(\vec{v_1} = 2 \hat{i} \, \text{m/s}\) - Particle 2: \(\vec{v_2} = 2 \hat{j} \, \text{m/s}\) ### Step 2: Calculate the velocity of the center of mass The formula for the velocity of the center of mass (\(\vec{v_{cm}}\)) of two particles of equal mass is: \[ \vec{v_{cm}} = \frac{m \vec{v_1} + m \vec{v_2}}{m + m} = \frac{\vec{v_1} + \vec{v_2}}{2} \] Substituting the values: \[ \vec{v_{cm}} = \frac{2 \hat{i} + 2 \hat{j}}{2} = \hat{i} + \hat{j} \, \text{m/s} \] ### Step 3: Identify the accelerations of the particles The accelerations of the particles are: - Particle 1: \(\vec{a_1} = 3 \hat{i} + 3 \hat{j} \, \text{m/s}^2\) - Particle 2: \(\vec{a_2} = 0 \, \text{m/s}^2\) ### Step 4: Calculate the acceleration of the center of mass The formula for the acceleration of the center of mass (\(\vec{a_{cm}}\)) is: \[ \vec{a_{cm}} = \frac{m \vec{a_1} + m \vec{a_2}}{m + m} = \frac{\vec{a_1} + \vec{a_2}}{2} \] Substituting the values: \[ \vec{a_{cm}} = \frac{(3 \hat{i} + 3 \hat{j}) + 0}{2} = \frac{3 \hat{i} + 3 \hat{j}}{2} = \frac{3}{2} \hat{i} + \frac{3}{2} \hat{j} \, \text{m/s}^2 \] ### Step 5: Analyze the direction of velocity and acceleration The velocity of the center of mass is \(\hat{i} + \hat{j}\), and the acceleration of the center of mass is \(\frac{3}{2} \hat{i} + \frac{3}{2} \hat{j}\). Both the velocity and acceleration vectors point in the same direction (the first quadrant). ### Step 6: Conclusion Since the velocity and acceleration of the center of mass are in the same direction, the center of mass will move in a straight line. Thus, the answer is: **The center of mass of the two particles moves in a straight line.**

To solve the problem, we need to determine the path of the center of mass of two particles given their velocities and accelerations. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the velocities of the particles The velocities of the two particles are given as: - Particle 1: \(\vec{v_1} = 2 \hat{i} \, \text{m/s}\) - Particle 2: \(\vec{v_2} = 2 \hat{j} \, \text{m/s}\) ### Step 2: Calculate the velocity of the center of mass ...
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