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In a system of particles 8 kg mass is su...

In a system of particles `8 kg` mass is subjected to a force of `16 N` along `+ve` x-axis and another `8 kg` is subjected to a force of `8 N` along `+ve` y-axis. The magnitude of acceleration of centre of mass and the angle made by it with x-axis are given respectively by :

A

`(sqrt(5))/(2) ms^-2, theta = 45^@`

B

`3sqrt(5) ms^-2, theta = tan^-1(2//3)`

C

`(sqrt(5))/(2) ms^-2, theta = tan^-1(1//2)`

D

`1 ms^-2, theta = tan^-1 sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

( c) `m_1 x_1 = m_2 x_2`
`vec a_(cm) = (vec F)/(m) =(16 hat i + 8 hatj)/(16) = hat i + (1)/(2) hat j`
`|vec a_(cm)| = sqrt(1^2 + ((1)/(2))^2) = (sqrt(5))/(2) m//s^2`
`tan theta = (1//2)/(1) rArr theta = tan^-1 ((1)/(2))`.
.
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Knowledge Check

  • In a system of particles 8 kg mass is subjected to a force of 16 N along + ve x -axis and another 8 kg mass is subjected to a force of 8 N along + ve y -axis. The magnitude of acceleration of centre of mass and the angle made by it with x -axis are given, respectively, by

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    `(sqrt(5))/2ms^(2),theta=45^(@)`
    B
    `3sqrt(5)ms^(2),theta=tan^(-1)(2/3)`
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    `(sqrt(5))/2ms^(2),theta=tan^(-1)(1/2)`
    D
    `1ms^(2),theta=tan^(-1)sqrt(3)`
  • A body of mass 10 kg is acted upon by two perpendicular forces , 6 N and 8 N . The resultant acceleration of the body is

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    `0.2 m s^(-2) ` at an angle of `tan^(-1)((4)/(3))` w.r.t. 6 N force
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    `1 m s^(-2)` at an angle of `tan^(-1) ((3)/(4))` w.r.t. 8 N force
    D
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