A rigid mass less rod of length `L` is hinged at its one end a weight `W` is hung at a distance `l(lt L)` from this end.
What is force `P` should be applied upwards at the other end so that the rod remains in equilibrium horizontally ?
.

Options

A. `(W(L - l))/(L)`
B. `(W(L - l))/(l)`
C. `(W l)/(L)`
D. `(W L)/(l)`

Answer

C

Explanation

( c) Taking torque about hinge `A`.
`PL - Wl = 0 rArr P = (W l)/(L)`.