The moment of inertia of an angular wheel shown in figure is `3200 kgm^2`. If the inner radius is `5 cm`, and the outer radius is `20 cm`, and the wheel is acted upon by the forces shown, then the angular acceleration of the wheel is.
.

Options

A. `10^-1 rad//s^2`
B. `10^-2 rad//s^2`
C. `10^-3 rad//s^2`
D. `10^-4 rad//s^2`

Answer

C

Explanation

( c) `tau = I prop rArr 10 xx (20)/(100) + (9 xx 20)/(100) - (12 xx 20)/(100) = 3200 prop`
`rArr prop = 10^-3 rad//s^2`.