For a particle of a mass `100 gm`, position and velocity at any instant are given as `10 hat i+ 6 hat j cm` and `vec v = 5 hat I cm//s`. Calculate the angular momentum about the point (1,1) cm.

Options

A. `25 xx 10^-5 (- hat k) kgm^2 s^-1`
B. `30 xx 10^-5 (- hat k) khm^2 s^-1`
C. `3 xx 10^-3 (- hat k) kgm^2 s^-1`
D. `25 xx 10^-4 (- hat k) kgm^2 s^-1`

Answer

A

Explanation

(a) `vec L = m(vec r xx vec c) = (100)/(1000) [(9 hat i+ 5 hat j)/(100)] xx (5 hat i)/(100)`
=`25 xx 10^-5 (-hat k) khm^2 s^-2`.