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In previous problem, the angular momentu...

In previous problem, the angular momentum of the projectile about the origin when it just before hits the ground should be.

A

`(- 2 mv_i^3 sin theta sin theta)/(g) hat k`

B

`(m v_i^3 sin theta^2 cos theta)/(2 g) hat k`

C

`(- mv_i^3 sin theta^2 cos theta)/(g) hat k`

D

`(2 mv_i^3 sin theta^2 cos theta)/(g) hat k`.

Text Solution

Verified by Experts

The correct Answer is:
A

(a) `vec L_2 = R hat i xx m vec v_2`, where
`R = (v_i^2 sin 2 theta)/(g) = (v_i^2 (2 sin theta cos theta))/(g)`
=`-m Rv_i sin theta hat k = (-2 mv_i^3 sin theta sin theta)/(g) hat k`.
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