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A vertical disc of mass 5 kg and radius ...

A vertical disc of mass `5 kg` and radius `50 cm` rests against a steo of height `25 cm` as shown in figure. What minimum horizontal force applied perpendicular to the axle will make the disc to climb the step ? Take `g = 10 m//s^2`.
.

A

50 N

B

`50 sqrt(3) N`

C

`25 N`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `y = 50 - 25 = 25 cm`
`x = sqrt(50^2 - 25^2) = 25 sqrt(3)`
`Fy = 5 gx`
`rArr (25) = 5 xx 10(25 sqrt(3))`
`rArr F = 50 sqrt(3) N`.
.
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