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A cubical block of side a is moving with...

A cubical block of side a is moving with velocity V on a horizontal smooth plane as shown in Figure. It hits a ridge at point O. The angular speed of the block after it hits O is

A

`3v//(4 a)`

B

`3 v//(2 a)`

C

`sqrt(3)//sqrt( 2 a)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A

(a) Apply conservation of angular momentum about `O`
`Mv(a)/(2) = [(Ma^2)/(6) + M((a)/(sqrt(2)))^2]omega`
`rArr omega = (3v)/(4a)`.
.
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