The angular velocity of second's hand of a watch will be.

Options

A. `(pi)/(60) rad//sec`
B. `(pi)/30 rad//sec`
C. `60 pi rad//sec`
D. `30 pi rad//sec`

Answer

B

Explanation

(b) We know that second's hand completes its revolution `(2 pi) "in" 60 sec`
:. `omega = (theta)/(t) = (2 pi)/(60) = (pi)/(30) rad//sec`.