A solid cylinder of mass `M` and radius `R` rolls without slipping down an inclined plane of length `L` and height `h`. What is the speed of its center of mass when the cylinder reaches its bottom

Options

A. `sqrt((3)/(4) gh)`
B. `sqrt((4)/(3)gh`
C. `sqrt(4) gh)`
D. `sqrt(2) gh)`

Answer

B

Explanation

(b) Applying principle of conservation of total mechanical energy
`mgh = (1)/(2) I((v^2)/(R^2)) + (1)/(2) mv^2`
Velocity at the bottom `v = sqrt((4)/(3) gh)`