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A mass m moves in a circles on a smooth ...

A mass `m` moves in a circles on a smooth horizontal plane with velocity `v_(0)` at a radius `R_(0)`. The mass is atteched to string which passes through a smooth hole in the plane as shown.
The tension in string is increased gradually and finally `m` moves in a cricle of radius `(R_(0))/(2)`. the final value of the kinetic energy is

A

`m v_0^2`

B

`2 mv_0^2`

C

`(1)/(4) mv_0^2`

D

`(1)/(2) mv_0^2`

Text Solution

Verified by Experts

The correct Answer is:
B

( c) Initial angular momentum `L_(initial) = mv_0 R`
Initial angular momentum `L_(initial) = mv ( R)/(2)`
Conservation of angular momentum
`m v_0 R_0 =m mv (R_0)/(2) rArr v = 2 v_0`
`KE = (1)/(2) mv^2 = 2 mv_0^2`.
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