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Two rotating bodies `A` and `B` of masses `m` and `2 m` with moments of inertia `I_A` and `I_B (I_B gt I_A)` have equal kinetic energy of rotation. If `L_A` and `L_B` are their angular momenta respectively, then.

A

`L_B gt L_A`

B

`L_A gt L_B`

C

`L_A = (L_B)/(2)`

D

`L_A = 2 L_B`

Text Solution

Verified by Experts

The correct Answer is:
A

(a) `K_A = K_B rArr (L_A^2)/(2 L_A) =(L_B^2)/(2 I_B)`
because `I_B gt I_A :. L_A^2 lt L_B^2 rArr L_A lt L_B`.
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