Figure shows a thin metallic triangular sheet `ABC`. The mass of the sheet is `M`. The moment of inertia of the sheet about side `AC` is :
.

Options

A. `(Ml^2)/(18)`
B. `(M l^2)/(12)`
C. `(ML^2)/(6)`
D. `(Ml^2)/(4)`

Answer

B

Explanation

(b) `h = l cos 45^@ = (l)/(sqrt(2))`
`I_(AC) = (1)/(2) Mh^2 = (1)/(6) M ((l)/(sqrt(2)))^2 = (Ml^2)/(12)`.
.