A wheel has angular acceleration of `3.0 rad//s^2` and an initial angular speed of `2.00 rad//s`. In a tine of `2 s` it has rotated through an angle (in radian) of

Options

A. 6
B. 12
C. 10
D. 4

Answer

C

Explanation

( c) We have `theta = omega_0 t + (1)/(2) prop t^2`…(ii)
Given, `prop = 3.0 rad//s^2, omega_0 = 2.0 rad//s,t = 2 s` ,brgt Hence, `theta = 2 xx 2 + (1)/(2) xx 3 xx (2)^2`
or `theta = 4 + 6 = 10 rad`.