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A particle performing uniform circular motion gas angular momentum `L`. If its angular frequency is double and its kinetic energy halved, then the new angular momentum is :

A

`(L)/(4)`

B

L

C

2 L

D

`(L)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `L = mr^2 omega` , Now Given `r' = (r)/(2) and omega' = omega`
`L' = m omega (r^2)/(4) = (L)/(4)`.
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