Consider a rod of mass `M` and length `L` pivoted at its centre is free to rotate in a vertical position plane. The rod is at rest in the vertical position. A bullet of mass `M` moving horizontally at a speed `v` strikes and embedded in one end of the rod. The angular velocity of the rod just after the collision will be.

Options

A. `v//L`
B. `2v//L`
C. `3v//2L`
D. `6v//L`

Answer

C

Explanation

( c) Apply conservation of angular momentum about `C`
`mv (L)/(2) = I omega`, where `I = M ((L)/(2))^2 + (ML^2)/(12)`
`rArr omega = (3v)/(2 L)`.