In the question number 5, the ercentage strain produced in the rod is

Options

A. `0.04%`
B. `0.08%`
C. `0.16%`
D. `0.24%`

Answer

C

Explanation

Elongation,
`triangleL=((F)/(A)L)/(Y)=((3.18xx10^8Nm^-2)(1m))/(2xx10^11Nm^-2)`
`=1.59xx10^-3m=1.59mm`
Strain produced in the rod is
Strain`=(triangleL)/(L)=(1.59xx10^-3m)/(1m)=1.59xx10^-3=0.16%`