In steel, the Young's modulus and the strain at the breaking point are `2xx10^11Nm^-2` and 0.15 respectively the stress at the break point for steel is

Options

A. `1.33xx10^11Nm^-2`
B. `1.33xx10^-12Nm^-2`
C. `7.5xx10^-3Nm^-2`
D. `3xx10^10Nm^-2`

Explanation

To find the stress at the breaking point for steel, we can use the relationship defined by Young's modulus. The formula for Young's modulus (E) is given by:

\[ E = \frac{\text{Stress}}{\text{Strain}} \]

Where:
- Stress is the force applied per unit area (in N/m²),
- Strain is the deformation experienced by the material (dimensionless).

Given:
- Young's modulus, \( E = 2 \times 10^{11} \, \text{N/m}^2 \)
- Strain at breaking point, \( \text{Strain} = 0.15 \)

We need to find the stress at the breaking point. Rearranging the formula for Young's modulus gives us:

\[ \text{Stress} = E \times \text{Strain} \]

Now, substituting the known values into the equation:

\[ \text{Stress} = (2 \times 10^{11} \, \text{N/m}^2) \times (0.15) \]

Calculating this gives:

\[ \text{Stress} = 2 \times 0.15 \times 10^{11} \]
\[ \text{Stress} = 0.30 \times 10^{11} \]
\[ \text{Stress} = 3.0 \times 10^{10} \, \text{N/m}^2 \]

Thus, the stress at the breaking point for steel is:

\[ \text{Stress} = 3.0 \times 10^{10} \, \text{N/m}^2 \]