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The product of Young's modulus of the ma...


The product of Young's modulus of the material of the wire with its cross sectional area is equal to its length. Find the parameters representing x and y axes of the curve as shown:

A

load and increase in length

B

stress and strain

C

Young's modulus and stress

D

Young's modulus and strain

Text Solution

Verified by Experts

The correct Answer is:
A

`Y=(((W)/(A)))/(((trianglel)/(l)))=trianglel=((l)/(YA))W`
Given, `YA=l` Som `(trianglel)/(W)=1`
also from curve its slope `=tan45^@=1`
So, x and y axes represent `W=andtrianglel`
`(epsi)/(W)=10^-1((m)/(Nm))`,`(epsi)/(W)=(trianglel)/(lW)`
From curve, slope`=tan45^@=1=(l)/(YA)=(trianglel)/(W)`
So, `(epsi)/(W)=10^-1=(1)/(l)((trianglel)/(W))=(1)/(l)`
`l=(1)/(10^-1)=10m=1000cm`
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