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Two wires of diameter 0.25 cm, one made ...

Two wires of diameter `0.25 cm`, one made of steel and other made of brass, are loaded as shown in the figure. The unloaded length of the steel wire is `1.5 m` and that of brass is `1.0 m`. Young's modulus of steel is `2.0 xx 10^(11)`Pa and that of brass is `1.0 xx 10^(11)` Pa. Compute the ratio of elongations of steel and brass wires. `(/_\l_("steel"))/(/_\l_("brass"))=?`

A

1.25

B

1.5

C

2

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
A

`trianglel_(brass)=(6gxx1.0)/(Axx1xx10^11)`
`trianglel_(steel)=(10gxx1.5)/(Axx2xx10^11)`
`(trianglel_(steel))/(trianglel_(brass))=(10gxx1.5)/(Axx2xx10^11)xx(Axx1xx10^11)/(6gxx1.0)`
`=(15)/(12)=(5)/(4)=1.25`
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