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The length of a rod is 20 cm and area of...

The length of a rod is 20 cm and area of cross section `2cm^2`. The Young's modulus of the amterial of wire is `1.4xx10^11(N)/(m^2)`. If the rod is compressed by 5 kg-wt along its length, then increase in the energy of the rod in joules will be

A

`8.57xx10^-6`

B

`22.5xx10^-4`

C

`9.8xx10^-5`

D

`45.0xx10^-5`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy`=(1)/(2)Fl=(1)/(2)xxFxx((FL)/(AY))=(1)/(2)xx(F^2L)/(AY)`
`=(1)/(2)xx((50)^2xx20xx10^-2)/(2x10^-4xx1.4xx10^(11))=8.57xx10^-6J`
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