When the load on a wire is slowly increased from `3kgwt` to `5 kg wt`, the elongation increases from `0.61` to `1.02 mm`. The work done during the extension of wire is

Options

A. `0.16J`
B. `0.016J`
C. `1.6J`
D. `16J`

Answer

B

Explanation

Work done `=(1)/(2)` stretching force `xx` extension.
Net work done in increasing the length from `0.164mm` to `1.02mm` is
`W-W_1=(1)/(2)xx5xx9.8xx1.02xx10^-3-(1)/(2)xx3xx9.8xx10^-3`
`=0.016J`
So the correct choice is (b).