The mass and length of a wire are M and L respectively. The density of the material of the wire is d. On applying the force F on the wire, the increase in length is l, then the Young's modulus of the material of the wire will be

Options

A. `(Fdl)/(Ml)`
B. `(FL)/(Mdl)`
C. `(FMl)/(dl)`
D. `(FdL^2)/(Ml)`

Answer

D

Explanation

`Y=(F)/(A)(L)/(l)=(FdL^2)/(Ml)`
As `M=`volume`xx`density`=AxxLxxd`
`A=(M)/(Ld)`