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The radius of a soap bubble is increased...

The radius of a soap bubble is increased from `(1)/(sqrtpi)` cm to `(2)/(sqrtpi)` cm. If the surface tension of water is `30"dynes"` per cm, then the work done will be

A

180 ergs

B

360 ergs

C

720 ergs

D

960 ergs

Text Solution

Verified by Experts

The correct Answer is:
C
`W=8piT(r_2^2-r_1^2)=8piT[((2)/(sqrtpi))^2-((1)/(sqrtpi))^2]`
`W=8xxpixx30xx(3)/(pi)=720ergs`
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