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Calculate the stress developed inside a tooth cavity filled with copper when hot tea at temperature of `57^(@)C` is drunk. You can take body (tooth) temperature to be `37^(@)C` and `alpha_(Cu) = 1.7 xx 10^(-5)//^(@)C` bulk modulus for copper `B_(Cu) = 140 xx 10^(9) N//m^(2)`.

A

`42 xx 10^(6) N//m^(2)`

B

`22 xx 10^(6) N//m^(2)`

C

`36 xx 10^(6) N//m^(2)`

D

`18 xx 10^(6) N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Given , decrease in temperature
`(Delta t) = 57-37 = 20^(@)C`
Coefficient of cubical expansion of copper
`gamma_(Cu) = 3 alpha_(Cu) = 5.1xx10^(-5)//^(@)C`
Let initial volume of the cavity be `V` and its volume increases by `Delta V` due to increase in temperature
`:. Delta V = gamma V Delta t`
`rArr (Delta V)/(V) = gamma Delta t`
Thermal stress produced = `B xx` Volumetric strain
`=B xx (Delta V)/(V) = B xx gamma Delta t`
`=140xx10^(9)xx(1.5xx10^(-5)xx20) = 42 xx 10^(6)N//m^(2)`
This is about `10^(3)` times of atmospheric pressure.
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What is the thermal stress developed inside a tooth cavity filled with copper when hot tea at temperature of 57^(@)C is drunk? You can take body (tooth) temperature to be 37^(@)C and alpha_(Cu) = 1.7 xx 10^(-5)//^(@)C and bulk modulus for copper = 14 xx 10^(10) N//m^(2) .

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Two rods of equal cross sections, one of copper and the other of steel, are joined to form a composite rod of length 2.0 m at 20^@C , the length of the copper rod is 0.5 m. When the temperature is raised to 120^@C , the length of composite rod increases to 2.002m. If the composite rod is fixed between two rigid walls and thus not allowed to expand, it is found that the lengths of the component rods also do not change with increase in temperature. Calculate Young's moulus of steel. (The coefficient of linear expansion of copper, alpha_c=1.6xx10^(-5@)C and Young's modulus of copper is 1.3xx10^(13)N//m^(2) ).

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