When 300 J of heat is added to `25 gm` of sample of a material its temperature rises from `25^(@)C` to `45^(@)C`. The thermal capacity of the sample and specific heat of the material are respectively given by

Options

A. `15 J//^(@)C, 600 J//Kg-^(@)C`
B. `600 J//^(@)C, 15 J//^(@)C-kg`
C. `150 J//^(@)C, 60 J//Kg-^(@)C`
D. None of these

Answer

A

Explanation

(i) Thermal energy
`TC = mc = (Q)/(Delta T) = (300)/(45-25) = 15J//^(@)C`
(ii) Specific heat is nothing but thermal capacity per unit mass
`C = (mc)/(m) = (15)/(25xx10^(-3)) = 600J//kg-^(@)C`.