A solid ball of mass `10 kg` at `40^(@)C` is gently placed in a liquid of mass `20 kg` at `20^(@)C` and of specific heat capacity `1 cal//gm-^(@)C`. When the thermal equilibrium is attained, temperature of the system is `35^(@)C`. The specific heat capacity of solid ball is. Neglect heat capacity of the vessel.

Options

A. `1 cal//gm-^(@)C`
B. `2 cal//gm-^(@)C`
C. `3 cal//gm-^(@)C`
D. `6 cal//gm-^(@)C`

Answer

D

Explanation

Heat gain by liquid = heat loss by solid ball.
`(10xxSxx5=20xx1xx15rArr S = 6 cal//gm-^(@)C`).