The amount of heat supplied to decrease the volume of an ice water mixture by `1 cm^(3)` without any change in temperature, is equal to: `(rho_("ice") = 0.9, rho_("water") = 80 cal//gm)`

Options

A. `360 cal`
B. `500 cal`
C. `720 cal`
D. None

Answer

C

Explanation

`x` gm ice convert into `x` gm water
`(x)/(0.9)-x=1rArrx=(0.9)/(0.1)=9`
`:. Q = 9xx80 =720cal`.